Moving on to ENGLISH SECTION

For each of the words in Capital letters, choose from among the answers, the word that is closest in meaning:

Q No. 1 GARRULOUS

(a) Arid (b) Hasty (c) Sociable (d) Quaint (e) Talkative



Q No. 2 INTER

(a) Bury (b) Amuse (c) Relate (d) Frequent (e) Abandon



Q No. 3 CHIMERICAL

(a) Developing (b) Brief (c) Distant (d) Economical (e) Fantastic

sorry for the delay

Mr. A buys an article for Rs.350 and sells to Rs.420, find his percentage profit.
C.P = Rs.350
S.P = Rs.420
Profit on C.P = 420 – 350 = 70
∴% profit on C.P = (70/350)*100 = 20 %

today's question

There are 728 students in a school, 162 come to the school by bus, 384 on bicycles
and the rest by walk. What percentage of students comes to the school by walk?
Sol.
Total number of students in the school = 728
Number of students who come by bus = 162
Number of students who come on bicycle = 384
Adding these two, we get 546.
728 – 546 = 182 students come by walk.
% of students who come by walk to the school=(182/728)*100=25%

07.01.2011

Two numbers are respectively 40% and 50% more than the third number. What
percentage of the 2nd number is the first number?
Sol.
First, assume the third number to be 100
∴First number = 140
Second number = 150
∴Percentage of the first number to the second number =(140/150)*100=288/3=93 1/3 %

Sorry for the delay friends

Q.Anand gets 15% more marks than Arun. What % of marks does Arun get less than Anand?
Sol.
Let us assume, Arun gets 100 marks. Anand gets 115 marks
In comparison to Anand, the % of marks Arun gets less than Anand
(15 *100) /115=13.04%

Jan 13 2010

Percentages, Profit and Loss
Percentages
1.x% =x/100
2.x% of y = xy/100
3.y% of x= yx/100
4.x% of y = y% of x
5.x=p %of y => x=py/100 => y= 100x/p

Example:

A man’s wages were reduced by 40%. Again, the reduced wages were increased by
40%. Find the percentage decrease in his original wages.
Sol.
Assume the initial wages to be Rs.100/-
Then wages after reduction of 40% = Rs.60
After 40% increase on the reduced wages, new wages =(140/100 )* 60 = Rs.84
Percentage of decrease on his initial wages = 100 – 84 = 16%

Jan 11-2011

The average of 30 innings of a batsman is 20 and another 20 innings is 30. What
is the average of all the innings?
Total of 50 innings = (30 × 20 + 20 × 30) = 1200
Average = 1200/0 =24

Jan 9, 2011

The average of 8 numbers is 21. Find the average of new set of numbers when 8
multiplies every number.
Total of 8 numbers = 168
Total of new 8 numbers = 168 × 8 = 1344
Average of new set= 1344/8=1688

Jan 8,2011

Five years ago, the average of Raja and Rani’s ages was 20 yrs. Now the average
age of Raja, Rani and Rama is 30 yrs. What will be Rama’s age 10 yrs hence?
Total age of Raja and Rani 5 years ago = 40
Total age of Raja and Rani now = 40 + 5 + 5 = 50
Total age of Raja, Rani and Rama now = 90
Rama’s age now = 90 – 50 = 40
Rama’s age after 10 years = 50

Jan 7,2011

Average:
 Average= Sum of all quantities / number of quantities


Question:

The average age of 30 kids is 9 years. If the teacher’s age is included, the
average age becomes 10 years. What is the teacher’s age?
Total age of 30 children = 30 × 9 = 270 yrs.
Average age of 30 children and 1 teacher = 10 yrs
Total of their ages = 31 × 10 = 310 yrs
Teacher’s age = 310 – 270 = 40

jan 6,2011

A and B run a km and A wins by 1 min.
A and C run a km and A wins by 375 mtrs.
B and C run a km and B wins by 30 sec
Find the time taken by B to run a km.
A beats B by 60 sec
B beats C by 30 sec
Hence A beats C by 90 secs. But we are given that A beats C by 375 mtrs. i.e. C
covers 375 mtrs in 90 sec.
Hence, time taken by C to cover 1 km = (90/375)* 1000
                                                           = 240sec

Time taken by B to cover 1 km = 240 – 30 = 210 secs.

05/01/2011

Race: A contest of speed in running, riding, driving, sailing or rowing is called a
race.
Dead-heat race: If all the persons contesting a race reach the goal at the same
time, then it is called a dead-heat race.

Ex:

A can run a km in 3 min and 54 sec and B can run the same distance in 4 min
and 20 sec. By what distance can A beat B?

A beats B by 26 sec.

Distance covered by B is 260 sec = 1000 mtrs
Distance covered by B is 26 sec = (1000/260)*26
                                                  = 100 mtrs.
Thus, A beats B by 100 mtrs.

Jan 4, 2011

A wheel rotates 12 times in a minute and moves 5 metres during each rotation.
What is the time taken for the wheel to move through 930 metres?
Sol:
For one rotation, distance moved = 5 metres
For 12 rotations, distance moved = 12 × 5 = 60 metres
Distance covered in 1 minute = 60 metres
Total distance covered by the wheel = 930 minutes
Total time taken = 930/60=15.5 minutes.

Question

A train 300 m. long passes a pole in 15 sec. Find the speed.
Sol:
Distance= 300 m
Time = 15 sec
∴ Speed =distance/time
                =300/15
                =20 m/sec

Jan 3, 2011

TIME AND DISTANCE
1. Speed v=s/t
where s = Total distance
t = Total time
2. s = vt
3.t=s/v
4. The relative velocity of two bodies moving at velocities u and v(u>v) in the same
direction is u – v.
5. The relative velocity of two bodies moving in opposite directions is u + v.
6. A train or a moving body of known length has to travel its own length in passing
a lamppost or a fixed body of insignificant size.
7. A train or a moving body must travel its own length plus the length of the
stationary body in question, if the train or the moving body has to pass a
stationary body i.e. a bridge, a railway platform etc.
8. Motion downstream or upstream:
Velocity of boat downstream = u + v
Velocity of boat upstream = u – v
Where ‘u’ is the velocity of the boat in still waters and ‘v’ is the
velocity of the stream.
9. If a man changes his speed in the ratio u : v, the corresponding ratio of times will
be
v : u

jan 2-2011

The efficiency of the first machine tool is 20% less than that of the 2nd
one. The first machine tool operated for 5 hours, whereas, the second one
operated for 4 hours and together they machined 4000 work pieces. Find the
number of work-pieces machined by the first machine tool.
Solution:
Efficiency of the two machine tools = 80: 100 = 4: 5
Time ratio of the two machine tools = 5: 4
∴ Work ratio of the two machine tools = 4×5: 5×4 = 20: 20 = 1: 1
Thus both the machine tools produced the same number of workpieces
Viz., 4000/2 = 2000

Alternative:
The second machine operating for 4 hours = first machine operating for 5
hours. Hence the first machine would produce 4000 pieces in 10 hours. In 5
hours it would have produced 2000 pieces.